3.669 \(\int \frac {(a+c x^2)^{3/2}}{(d+e x)^{9/2}} \, dx\)

Optimal. Leaf size=491 \[ -\frac {8 \sqrt {-a} c^{3/2} \sqrt {\frac {c x^2}{a}+1} \left (5 a e^2+4 c d^2\right ) \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {-a} e+\sqrt {c} d}} F\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{35 e^4 \sqrt {a+c x^2} \sqrt {d+e x} \left (a e^2+c d^2\right )}+\frac {32 \sqrt {-a} c^{5/2} d \sqrt {\frac {c x^2}{a}+1} \sqrt {d+e x} \left (2 a e^2+c d^2\right ) E\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{35 e^4 \sqrt {a+c x^2} \left (a e^2+c d^2\right )^2 \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {-a} e+\sqrt {c} d}}}+\frac {32 c^2 d \sqrt {a+c x^2} \left (2 a e^2+c d^2\right )}{35 e^3 \sqrt {d+e x} \left (a e^2+c d^2\right )^2}-\frac {4 c \sqrt {a+c x^2} \left (e x \left (5 a e^2+7 c d^2\right )+2 d \left (a e^2+2 c d^2\right )\right )}{35 e^3 (d+e x)^{5/2} \left (a e^2+c d^2\right )}-\frac {2 \left (a+c x^2\right )^{3/2}}{7 e (d+e x)^{7/2}} \]

[Out]

-2/7*(c*x^2+a)^(3/2)/e/(e*x+d)^(7/2)-4/35*c*(2*d*(a*e^2+2*c*d^2)+e*(5*a*e^2+7*c*d^2)*x)*(c*x^2+a)^(1/2)/e^3/(a
*e^2+c*d^2)/(e*x+d)^(5/2)+32/35*c^2*d*(2*a*e^2+c*d^2)*(c*x^2+a)^(1/2)/e^3/(a*e^2+c*d^2)^2/(e*x+d)^(1/2)+32/35*
c^(5/2)*d*(2*a*e^2+c*d^2)*EllipticE(1/2*(1-x*c^(1/2)/(-a)^(1/2))^(1/2)*2^(1/2),(-2*a*e/(-a*e+d*(-a)^(1/2)*c^(1
/2)))^(1/2))*(-a)^(1/2)*(e*x+d)^(1/2)*(c*x^2/a+1)^(1/2)/e^4/(a*e^2+c*d^2)^2/(c*x^2+a)^(1/2)/((e*x+d)*c^(1/2)/(
e*(-a)^(1/2)+d*c^(1/2)))^(1/2)-8/35*c^(3/2)*(5*a*e^2+4*c*d^2)*EllipticF(1/2*(1-x*c^(1/2)/(-a)^(1/2))^(1/2)*2^(
1/2),(-2*a*e/(-a*e+d*(-a)^(1/2)*c^(1/2)))^(1/2))*(-a)^(1/2)*(c*x^2/a+1)^(1/2)*((e*x+d)*c^(1/2)/(e*(-a)^(1/2)+d
*c^(1/2)))^(1/2)/e^4/(a*e^2+c*d^2)/(e*x+d)^(1/2)/(c*x^2+a)^(1/2)

________________________________________________________________________________________

Rubi [A]  time = 0.48, antiderivative size = 491, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 7, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {733, 811, 835, 844, 719, 424, 419} \[ \frac {32 c^2 d \sqrt {a+c x^2} \left (2 a e^2+c d^2\right )}{35 e^3 \sqrt {d+e x} \left (a e^2+c d^2\right )^2}-\frac {8 \sqrt {-a} c^{3/2} \sqrt {\frac {c x^2}{a}+1} \left (5 a e^2+4 c d^2\right ) \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {-a} e+\sqrt {c} d}} F\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{35 e^4 \sqrt {a+c x^2} \sqrt {d+e x} \left (a e^2+c d^2\right )}+\frac {32 \sqrt {-a} c^{5/2} d \sqrt {\frac {c x^2}{a}+1} \sqrt {d+e x} \left (2 a e^2+c d^2\right ) E\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{35 e^4 \sqrt {a+c x^2} \left (a e^2+c d^2\right )^2 \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {-a} e+\sqrt {c} d}}}-\frac {4 c \sqrt {a+c x^2} \left (e x \left (5 a e^2+7 c d^2\right )+2 d \left (a e^2+2 c d^2\right )\right )}{35 e^3 (d+e x)^{5/2} \left (a e^2+c d^2\right )}-\frac {2 \left (a+c x^2\right )^{3/2}}{7 e (d+e x)^{7/2}} \]

Antiderivative was successfully verified.

[In]

Int[(a + c*x^2)^(3/2)/(d + e*x)^(9/2),x]

[Out]

(32*c^2*d*(c*d^2 + 2*a*e^2)*Sqrt[a + c*x^2])/(35*e^3*(c*d^2 + a*e^2)^2*Sqrt[d + e*x]) - (4*c*(2*d*(2*c*d^2 + a
*e^2) + e*(7*c*d^2 + 5*a*e^2)*x)*Sqrt[a + c*x^2])/(35*e^3*(c*d^2 + a*e^2)*(d + e*x)^(5/2)) - (2*(a + c*x^2)^(3
/2))/(7*e*(d + e*x)^(7/2)) + (32*Sqrt[-a]*c^(5/2)*d*(c*d^2 + 2*a*e^2)*Sqrt[d + e*x]*Sqrt[1 + (c*x^2)/a]*Ellipt
icE[ArcSin[Sqrt[1 - (Sqrt[c]*x)/Sqrt[-a]]/Sqrt[2]], (-2*a*e)/(Sqrt[-a]*Sqrt[c]*d - a*e)])/(35*e^4*(c*d^2 + a*e
^2)^2*Sqrt[(Sqrt[c]*(d + e*x))/(Sqrt[c]*d + Sqrt[-a]*e)]*Sqrt[a + c*x^2]) - (8*Sqrt[-a]*c^(3/2)*(4*c*d^2 + 5*a
*e^2)*Sqrt[(Sqrt[c]*(d + e*x))/(Sqrt[c]*d + Sqrt[-a]*e)]*Sqrt[1 + (c*x^2)/a]*EllipticF[ArcSin[Sqrt[1 - (Sqrt[c
]*x)/Sqrt[-a]]/Sqrt[2]], (-2*a*e)/(Sqrt[-a]*Sqrt[c]*d - a*e)])/(35*e^4*(c*d^2 + a*e^2)*Sqrt[d + e*x]*Sqrt[a +
c*x^2])

Rule 419

Int[1/(Sqrt[(a_) + (b_.)*(x_)^2]*Sqrt[(c_) + (d_.)*(x_)^2]), x_Symbol] :> Simp[(1*EllipticF[ArcSin[Rt[-(d/c),
2]*x], (b*c)/(a*d)])/(Sqrt[a]*Sqrt[c]*Rt[-(d/c), 2]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] &
& GtQ[a, 0] &&  !(NegQ[b/a] && SimplerSqrtQ[-(b/a), -(d/c)])

Rule 424

Int[Sqrt[(a_) + (b_.)*(x_)^2]/Sqrt[(c_) + (d_.)*(x_)^2], x_Symbol] :> Simp[(Sqrt[a]*EllipticE[ArcSin[Rt[-(d/c)
, 2]*x], (b*c)/(a*d)])/(Sqrt[c]*Rt[-(d/c), 2]), x] /; FreeQ[{a, b, c, d}, x] && NegQ[d/c] && GtQ[c, 0] && GtQ[
a, 0]

Rule 719

Int[((d_) + (e_.)*(x_))^(m_)/Sqrt[(a_) + (c_.)*(x_)^2], x_Symbol] :> Dist[(2*a*Rt[-(c/a), 2]*(d + e*x)^m*Sqrt[
1 + (c*x^2)/a])/(c*Sqrt[a + c*x^2]*((c*(d + e*x))/(c*d - a*e*Rt[-(c/a), 2]))^m), Subst[Int[(1 + (2*a*e*Rt[-(c/
a), 2]*x^2)/(c*d - a*e*Rt[-(c/a), 2]))^m/Sqrt[1 - x^2], x], x, Sqrt[(1 - Rt[-(c/a), 2]*x)/2]], x] /; FreeQ[{a,
c, d, e}, x] && NeQ[c*d^2 + a*e^2, 0] && EqQ[m^2, 1/4]

Rule 733

Int[((d_) + (e_.)*(x_))^(m_)*((a_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[((d + e*x)^(m + 1)*(a + c*x^2)^p)/(
e*(m + 1)), x] - Dist[(2*c*p)/(e*(m + 1)), Int[x*(d + e*x)^(m + 1)*(a + c*x^2)^(p - 1), x], x] /; FreeQ[{a, c,
d, e, m}, x] && NeQ[c*d^2 + a*e^2, 0] && GtQ[p, 0] && (IntegerQ[p] || LtQ[m, -1]) && NeQ[m, -1] &&  !ILtQ[m +
2*p + 1, 0] && IntQuadraticQ[a, 0, c, d, e, m, p, x]

Rule 811

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> -Simp[((d + e*x)^
(m + 1)*(a + c*x^2)^p*((d*g - e*f*(m + 2))*(c*d^2 + a*e^2) - 2*c*d^2*p*(e*f - d*g) - e*(g*(m + 1)*(c*d^2 + a*e
^2) + 2*c*d*p*(e*f - d*g))*x))/(e^2*(m + 1)*(m + 2)*(c*d^2 + a*e^2)), x] - Dist[p/(e^2*(m + 1)*(m + 2)*(c*d^2
+ a*e^2)), Int[(d + e*x)^(m + 2)*(a + c*x^2)^(p - 1)*Simp[2*a*c*e*(e*f - d*g)*(m + 2) - c*(2*c*d*(d*g*(2*p + 1
) - e*f*(m + 2*p + 2)) - 2*a*e^2*g*(m + 1))*x, x], x], x] /; FreeQ[{a, c, d, e, f, g}, x] && NeQ[c*d^2 + a*e^2
, 0] && GtQ[p, 0] && LtQ[m, -2] && LtQ[m + 2*p, 0] &&  !ILtQ[m + 2*p + 3, 0]

Rule 835

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Simp[((e*f - d*g)
*(d + e*x)^(m + 1)*(a + c*x^2)^(p + 1))/((m + 1)*(c*d^2 + a*e^2)), x] + Dist[1/((m + 1)*(c*d^2 + a*e^2)), Int[
(d + e*x)^(m + 1)*(a + c*x^2)^p*Simp[(c*d*f + a*e*g)*(m + 1) - c*(e*f - d*g)*(m + 2*p + 3)*x, x], x], x] /; Fr
eeQ[{a, c, d, e, f, g, p}, x] && NeQ[c*d^2 + a*e^2, 0] && LtQ[m, -1] && (IntegerQ[m] || IntegerQ[p] || Integer
sQ[2*m, 2*p])

Rule 844

Int[((d_.) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[g/e, Int[(d
+ e*x)^(m + 1)*(a + c*x^2)^p, x], x] + Dist[(e*f - d*g)/e, Int[(d + e*x)^m*(a + c*x^2)^p, x], x] /; FreeQ[{a,
c, d, e, f, g, m, p}, x] && NeQ[c*d^2 + a*e^2, 0] &&  !IGtQ[m, 0]

Rubi steps

\begin {align*} \int \frac {\left (a+c x^2\right )^{3/2}}{(d+e x)^{9/2}} \, dx &=-\frac {2 \left (a+c x^2\right )^{3/2}}{7 e (d+e x)^{7/2}}+\frac {(6 c) \int \frac {x \sqrt {a+c x^2}}{(d+e x)^{7/2}} \, dx}{7 e}\\ &=-\frac {4 c \left (2 d \left (2 c d^2+a e^2\right )+e \left (7 c d^2+5 a e^2\right ) x\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right ) (d+e x)^{5/2}}-\frac {2 \left (a+c x^2\right )^{3/2}}{7 e (d+e x)^{7/2}}-\frac {(4 c) \int \frac {3 a c d e-c \left (4 c d^2+5 a e^2\right ) x}{(d+e x)^{3/2} \sqrt {a+c x^2}} \, dx}{35 e^3 \left (c d^2+a e^2\right )}\\ &=\frac {32 c^2 d \left (c d^2+2 a e^2\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right )^2 \sqrt {d+e x}}-\frac {4 c \left (2 d \left (2 c d^2+a e^2\right )+e \left (7 c d^2+5 a e^2\right ) x\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right ) (d+e x)^{5/2}}-\frac {2 \left (a+c x^2\right )^{3/2}}{7 e (d+e x)^{7/2}}+\frac {(8 c) \int \frac {\frac {1}{2} a c e \left (c d^2+5 a e^2\right )-2 c^2 d \left (c d^2+2 a e^2\right ) x}{\sqrt {d+e x} \sqrt {a+c x^2}} \, dx}{35 e^3 \left (c d^2+a e^2\right )^2}\\ &=\frac {32 c^2 d \left (c d^2+2 a e^2\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right )^2 \sqrt {d+e x}}-\frac {4 c \left (2 d \left (2 c d^2+a e^2\right )+e \left (7 c d^2+5 a e^2\right ) x\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right ) (d+e x)^{5/2}}-\frac {2 \left (a+c x^2\right )^{3/2}}{7 e (d+e x)^{7/2}}-\frac {\left (16 c^3 d \left (c d^2+2 a e^2\right )\right ) \int \frac {\sqrt {d+e x}}{\sqrt {a+c x^2}} \, dx}{35 e^4 \left (c d^2+a e^2\right )^2}+\frac {\left (4 c^2 \left (4 c d^2+5 a e^2\right )\right ) \int \frac {1}{\sqrt {d+e x} \sqrt {a+c x^2}} \, dx}{35 e^4 \left (c d^2+a e^2\right )}\\ &=\frac {32 c^2 d \left (c d^2+2 a e^2\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right )^2 \sqrt {d+e x}}-\frac {4 c \left (2 d \left (2 c d^2+a e^2\right )+e \left (7 c d^2+5 a e^2\right ) x\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right ) (d+e x)^{5/2}}-\frac {2 \left (a+c x^2\right )^{3/2}}{7 e (d+e x)^{7/2}}-\frac {\left (32 a c^{5/2} d \left (c d^2+2 a e^2\right ) \sqrt {d+e x} \sqrt {1+\frac {c x^2}{a}}\right ) \operatorname {Subst}\left (\int \frac {\sqrt {1+\frac {2 a \sqrt {c} e x^2}{\sqrt {-a} \left (c d-\frac {a \sqrt {c} e}{\sqrt {-a}}\right )}}}{\sqrt {1-x^2}} \, dx,x,\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )}{35 \sqrt {-a} e^4 \left (c d^2+a e^2\right )^2 \sqrt {\frac {c (d+e x)}{c d-\frac {a \sqrt {c} e}{\sqrt {-a}}}} \sqrt {a+c x^2}}+\frac {\left (8 a c^{3/2} \left (4 c d^2+5 a e^2\right ) \sqrt {\frac {c (d+e x)}{c d-\frac {a \sqrt {c} e}{\sqrt {-a}}}} \sqrt {1+\frac {c x^2}{a}}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-x^2} \sqrt {1+\frac {2 a \sqrt {c} e x^2}{\sqrt {-a} \left (c d-\frac {a \sqrt {c} e}{\sqrt {-a}}\right )}}} \, dx,x,\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )}{35 \sqrt {-a} e^4 \left (c d^2+a e^2\right ) \sqrt {d+e x} \sqrt {a+c x^2}}\\ &=\frac {32 c^2 d \left (c d^2+2 a e^2\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right )^2 \sqrt {d+e x}}-\frac {4 c \left (2 d \left (2 c d^2+a e^2\right )+e \left (7 c d^2+5 a e^2\right ) x\right ) \sqrt {a+c x^2}}{35 e^3 \left (c d^2+a e^2\right ) (d+e x)^{5/2}}-\frac {2 \left (a+c x^2\right )^{3/2}}{7 e (d+e x)^{7/2}}+\frac {32 \sqrt {-a} c^{5/2} d \left (c d^2+2 a e^2\right ) \sqrt {d+e x} \sqrt {1+\frac {c x^2}{a}} E\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{35 e^4 \left (c d^2+a e^2\right )^2 \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {c} d+\sqrt {-a} e}} \sqrt {a+c x^2}}-\frac {8 \sqrt {-a} c^{3/2} \left (4 c d^2+5 a e^2\right ) \sqrt {\frac {\sqrt {c} (d+e x)}{\sqrt {c} d+\sqrt {-a} e}} \sqrt {1+\frac {c x^2}{a}} F\left (\sin ^{-1}\left (\frac {\sqrt {1-\frac {\sqrt {c} x}{\sqrt {-a}}}}{\sqrt {2}}\right )|-\frac {2 a e}{\sqrt {-a} \sqrt {c} d-a e}\right )}{35 e^4 \left (c d^2+a e^2\right ) \sqrt {d+e x} \sqrt {a+c x^2}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [C]  time = 3.22, size = 659, normalized size = 1.34 \[ \frac {2 \left (-e^2 \left (a+c x^2\right ) \left (-16 c^2 d (d+e x)^3 \left (2 a e^2+c d^2\right )-16 c d (d+e x) \left (a e^2+c d^2\right )^2+c (d+e x)^2 \left (15 a e^2+19 c d^2\right ) \left (a e^2+c d^2\right )+5 \left (a e^2+c d^2\right )^3\right )-\frac {4 c^2 (d+e x)^3 \left (-\sqrt {a} e (d+e x)^{3/2} \left (5 i a^{3/2} e^3+i \sqrt {a} c d^2 e+8 a \sqrt {c} d e^2+4 c^{3/2} d^3\right ) \sqrt {\frac {e \left (x+\frac {i \sqrt {a}}{\sqrt {c}}\right )}{d+e x}} \sqrt {-\frac {-e x+\frac {i \sqrt {a} e}{\sqrt {c}}}{d+e x}} F\left (i \sinh ^{-1}\left (\frac {\sqrt {-d-\frac {i \sqrt {a} e}{\sqrt {c}}}}{\sqrt {d+e x}}\right )|\frac {\sqrt {c} d-i \sqrt {a} e}{\sqrt {c} d+i \sqrt {a} e}\right )+4 \sqrt {c} d (d+e x)^{3/2} \left (2 a^{3/2} e^3+\sqrt {a} c d^2 e-2 i a \sqrt {c} d e^2-i c^{3/2} d^3\right ) \sqrt {\frac {e \left (x+\frac {i \sqrt {a}}{\sqrt {c}}\right )}{d+e x}} \sqrt {-\frac {-e x+\frac {i \sqrt {a} e}{\sqrt {c}}}{d+e x}} E\left (i \sinh ^{-1}\left (\frac {\sqrt {-d-\frac {i \sqrt {a} e}{\sqrt {c}}}}{\sqrt {d+e x}}\right )|\frac {\sqrt {c} d-i \sqrt {a} e}{\sqrt {c} d+i \sqrt {a} e}\right )+4 d e^2 \sqrt {-d-\frac {i \sqrt {a} e}{\sqrt {c}}} \left (2 a^2 e^2+a c \left (d^2+2 e^2 x^2\right )+c^2 d^2 x^2\right )\right )}{\sqrt {-d-\frac {i \sqrt {a} e}{\sqrt {c}}}}\right )}{35 e^5 \sqrt {a+c x^2} (d+e x)^{7/2} \left (a e^2+c d^2\right )^2} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + c*x^2)^(3/2)/(d + e*x)^(9/2),x]

[Out]

(2*(-(e^2*(a + c*x^2)*(5*(c*d^2 + a*e^2)^3 - 16*c*d*(c*d^2 + a*e^2)^2*(d + e*x) + c*(c*d^2 + a*e^2)*(19*c*d^2
+ 15*a*e^2)*(d + e*x)^2 - 16*c^2*d*(c*d^2 + 2*a*e^2)*(d + e*x)^3)) - (4*c^2*(d + e*x)^3*(4*d*e^2*Sqrt[-d - (I*
Sqrt[a]*e)/Sqrt[c]]*(2*a^2*e^2 + c^2*d^2*x^2 + a*c*(d^2 + 2*e^2*x^2)) + 4*Sqrt[c]*d*((-I)*c^(3/2)*d^3 + Sqrt[a
]*c*d^2*e - (2*I)*a*Sqrt[c]*d*e^2 + 2*a^(3/2)*e^3)*Sqrt[(e*((I*Sqrt[a])/Sqrt[c] + x))/(d + e*x)]*Sqrt[-(((I*Sq
rt[a]*e)/Sqrt[c] - e*x)/(d + e*x))]*(d + e*x)^(3/2)*EllipticE[I*ArcSinh[Sqrt[-d - (I*Sqrt[a]*e)/Sqrt[c]]/Sqrt[
d + e*x]], (Sqrt[c]*d - I*Sqrt[a]*e)/(Sqrt[c]*d + I*Sqrt[a]*e)] - Sqrt[a]*e*(4*c^(3/2)*d^3 + I*Sqrt[a]*c*d^2*e
+ 8*a*Sqrt[c]*d*e^2 + (5*I)*a^(3/2)*e^3)*Sqrt[(e*((I*Sqrt[a])/Sqrt[c] + x))/(d + e*x)]*Sqrt[-(((I*Sqrt[a]*e)/
Sqrt[c] - e*x)/(d + e*x))]*(d + e*x)^(3/2)*EllipticF[I*ArcSinh[Sqrt[-d - (I*Sqrt[a]*e)/Sqrt[c]]/Sqrt[d + e*x]]
, (Sqrt[c]*d - I*Sqrt[a]*e)/(Sqrt[c]*d + I*Sqrt[a]*e)]))/Sqrt[-d - (I*Sqrt[a]*e)/Sqrt[c]]))/(35*e^5*(c*d^2 + a
*e^2)^2*(d + e*x)^(7/2)*Sqrt[a + c*x^2])

________________________________________________________________________________________

fricas [F]  time = 0.95, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (c x^{2} + a\right )}^{\frac {3}{2}} \sqrt {e x + d}}{e^{5} x^{5} + 5 \, d e^{4} x^{4} + 10 \, d^{2} e^{3} x^{3} + 10 \, d^{3} e^{2} x^{2} + 5 \, d^{4} e x + d^{5}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+a)^(3/2)/(e*x+d)^(9/2),x, algorithm="fricas")

[Out]

integral((c*x^2 + a)^(3/2)*sqrt(e*x + d)/(e^5*x^5 + 5*d*e^4*x^4 + 10*d^2*e^3*x^3 + 10*d^3*e^2*x^2 + 5*d^4*e*x
+ d^5), x)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (c x^{2} + a\right )}^{\frac {3}{2}}}{{\left (e x + d\right )}^{\frac {9}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+a)^(3/2)/(e*x+d)^(9/2),x, algorithm="giac")

[Out]

integrate((c*x^2 + a)^(3/2)/(e*x + d)^(9/2), x)

________________________________________________________________________________________

maple [B]  time = 0.17, size = 5277, normalized size = 10.75 \[ \text {output too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x^2+a)^(3/2)/(e*x+d)^(9/2),x)

[Out]

result too large to display

________________________________________________________________________________________

maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (c x^{2} + a\right )}^{\frac {3}{2}}}{{\left (e x + d\right )}^{\frac {9}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x^2+a)^(3/2)/(e*x+d)^(9/2),x, algorithm="maxima")

[Out]

integrate((c*x^2 + a)^(3/2)/(e*x + d)^(9/2), x)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (c\,x^2+a\right )}^{3/2}}{{\left (d+e\,x\right )}^{9/2}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + c*x^2)^(3/2)/(d + e*x)^(9/2),x)

[Out]

int((a + c*x^2)^(3/2)/(d + e*x)^(9/2), x)

________________________________________________________________________________________

sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (a + c x^{2}\right )^{\frac {3}{2}}}{\left (d + e x\right )^{\frac {9}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x**2+a)**(3/2)/(e*x+d)**(9/2),x)

[Out]

Integral((a + c*x**2)**(3/2)/(d + e*x)**(9/2), x)

________________________________________________________________________________________